Read File

Classic Servoy
1

Hello
I have this route with many xml files to import
C:\xml\groups\group1.xml
C:\xml\groups\group2.xml
C:\xml\groups\group3.xml
…
…
…

I have many xml, that I need read and import the conten to my application.
How can I read each path of each file to import?

Thanks.

2

What do you mean by “route”?

If you have the paths in a string, separated by newlines, you can do

var _path_array = string.split("\n");
```to get a array of the paths.

After that you can loop through your array and use the file plugin to read the contents of the files:

for (var i = 0; i < _path_array.length; i++) {
_content = plugins.file.readTXTFile(_path_array[i]);
}

3

Yes, I have the folowing path:
c:\xml\groups\group1.xml
c:\xml\groups\group2.xml
c:\xml\grups\groups3.xml
…
…
I have another aplicattion (no Servoy), that continuosly generate XML files.
I need read this files to import to my Servoy solution
The path is always the same, only change the name of the fail
When I import the file, I delete the file, which I have the file, group1.xml, group2.xml,…, group15050.xml etc…
I need know how many files there are in the path c:\xml\groups, and read every one and then delete.

Thanks.

4

Ok, then you need something like this:

	var _dir = plugins.file.convertToJSFile("C:/xml/groups/);
	var _files = _dir.listFiles();
	
	var _content;
	for (var i = 0; i < _files.length; i++) {
		_content = plugins.file.readTXTFile(_files[i]);
		//do stuff
		plugins.file.deleteFile(_files[i]);
	}
5

Thanks Joas, is perfect.