Short answer: you can’t.
What you could do however is use a calculation that shows a (button) image depending on the status.
And an onAction method on that calculation field that checks the record status and acts accordingly.
Like I said you can’t set a property of a button in a specific row. What you can do however is mimicking this behavior by using a calculation that shows an image depending on your status field (of that same record).
So you are not setting any form properties but you are showing an image (of a button) like so: