question application.showURL()

Hello,

I want to make open a browser with some parameters something like this:

application.showURL("http://www.google.com","_blank","height=500,width=915,status=no,toolbar=no,menubar=no,left=50,top=100,scrollbars=no,location=no,directories=no,resizable=no") 

but this line of code opens a normal browser without the influence of the parameters.

What is not ok please with the code ?

Thank you.